| Methods / ti-cas.org | |
| Calculation of a sum after decomposition in simple elements. |
| Objectives | To show how to make such a study with TI-89-92-92 Plus |
| Public |
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| Idea | O.Miclo |
Example
1) DECOMPOSITION
IN SIMPLE ELEMENTS OF
2) CALCULATE
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The value of the sum is obtained by éxécutant the command S(1/(4n^2-1), N, 1, inf): 1/2
It is of course not the method of resolution which you await from this article!
like we lay out of a decomposition in simple element simples of our function, the method of resolution consist with evaluate the 2 element of this nap, for different value of " N ".
The goal consists in finding the values being cancelled between them according to the values of " N "... N evolving/moving between 1 and p.
Here an example with N = p-1
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... is -1/(2(2p-1)) + 1/(2(2p-3)) for n=p-1 |
A table of values must be created, and this can be carried out with the machine.
First of all, it be useful to announce that the function LEAVE of TI-89 and 92 Plus can we enable to extract easily the 2 component of this sum, as it show the screen following:

Installation Of Table (Sorter):

Only 3 columns are useful for us: one can increase the dimension of each cell with [ diamant]+[F ]

C1 will contain various values of N: 1, 2, 3... p-2, p-1, p
C2 will be the evaluation
of the left part of
for the different ones from C1
C2 will be the evaluation
of the right part of
for
the different ones from C1
| Let us start with the column C1: |
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| The column c2 is supplemented automatically. |
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After creation of C3, here the complete table:

By drawing this picture on your copy, it is easy to see which values must be eliminated:
And according to the direct result (S(1/(4n^2-1), N, 1, inf) = 1/2) returned by your TI-89.92, you can even guess the boxes which are to be eliminated!!!
