| Methods / ti-cas.org | |
| Geometrical application with complex numbers |
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The study of the complex
numbers is rich. We will be interested in this article to the geometrical transformations,
like complex homotheties, rotations, similarities and inversions. The symbolic
computations will be carried out with a TI-89 …and you will be able to see how
to transform a line to a circle (!) with the fabulous CabriII software.
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* Translation:
The specific transformation associated with z®
Z=z+b (bÎ C, b=a
+ib ) is a translation of vector
Yes … this screen comes from a TI-89!!! Example with the image by Z=z-i of the line of equation y=x-1 (passing by A(0,-1) and B(2,1)). |
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* Rotation
: The specific transformation associated with z®
Z= The opposite screen shows the image of the line y=x-1 by Z=z*i, which is a rotation from angle +p /2 compared to the point O. |
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* Homothety: The specific transformation associated with z® Z=k* b B is a homothety of center O and ratio K. Example with the image by Z=3*z of y=x-1 |
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* Direct plane
similarity : The specific transformation associated
with z® Z=
is a direct plane similarity of center O, of ratio r
, angle q [2p
]. One notes
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The similarity associates two transformations: Homothety and Rotation. For a
Rotation or Similarity, it is thus necessary to convert a complex expression
into polar format. Let us notice all the same that the " Rotation " example
is a similarity ![]()
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The opposite screen shows the image by Z=3*i*z of our line. It's a similarity (rotation + homothety)
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* Complex inversion
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The image of a line passing by O (O excluded) is a line. A point M(x,y) placed on this line has for image M(1/x,1/y).
We created the segment [ CD ], the center of the circle (medium of [ CD ]), then the circle. We checked if the circle passes by O (property) …although O is excluded from the circle …a drug please !!! |
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An invariant point is a point which, after transformation did not moved..
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It is thus necessary to solve |
To avoid the automatic simplification of a complex expression by z=a+i*b, let us replace i by variable i
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So that the equality is checked, it is necessary that the numerator is null:
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The two invariants points are A(-1 ;1) and B(1 ;1) |
getNum & part allows us to easily extract the numerator of this expression, and zeros enables us to obtain the roots of this last expression (by change i by i)
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Show that if z=i*y then Z=i*Y
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While using |
The TI-89 can carry out this type of calculation easily:
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Put Z in the form One carries out the Euclidean division of i× z+2 par z-i
PropFrac enables us to obtain the desired form … but it will be necessary to replace i by i in order to fight against automatic simplification a+i*b
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Let us use this decomposition to build image per T of the line x-y-1=0.
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- Line y=x-1 passing by A(0,-1) and B(2,1) |
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After having created a unit vector |
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After having created a second unit vector |
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This article shows that the TI-89 is an exceptional tool : the student can rock between two environments, CAS and geometry.
The geometry of TI-89.92 Plus, with CABRI, is a powerful tool for investigation and of discovered of a broad variety of models, relations and connections in mathematics.
CABRI-GEOMETRIE allows the students to follow the advance of the mathematical discovery through demonstrations while exploring and by learning the principles.
Also see in GEOMETRY heading how to carry out a macro-construction allowing to obtain the complex inversion of a line.