| Methods / ti-cas.org | |
| Integral calculus (C.A.S. v1.00) |
| Objectives | Resolution of 6 exercises posed at the time of the oral examinations of various contests of large scientific or commercial schools. |
| Public |
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| Prérequis |
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| Idea | H.Lemberg |
Calculate
(Central P')




| The integral is also obtained quickly: |
|
Calculate
(Ensi)
|
|
No problem
for the TI-92.
Time to say "ouf", and the answer appears ! Let us pass to a more difficult exercise... |
Calculate f(x) =
(Po X Me)
Determine if F is a rational fraction and determine F then.

The TI-92 meets only few problems to solve this exercise.
The solution is:
Thus F is a rational fraction if and only if a=-10/3.
In this case, ![]()

Calculate
f(x) =
(Central
P')
|
|
The
TI-92 returns an approximate value, moreover rather quickly, which is the
sign that it " refuses " to make a symbolic calculation.
It remains us to help it. |
Like 0<=x<=1, let us pose x=sin(t).
Thus,
= ![]()

This change of variable can be assisted by the program present on this site.
| After
a very long time very, one obtains this result .
One would like right knowledge how y to arrive. One will be able obviously to write a programme of integration by parts. |
|
Calculate
f(x) =
(X
Me)
| This
is already a more delicate exercise. One should not hope to see TI-89.92 Plus
(v1.00) calculating cete integral generalized.
Here, our computer will help us to ensure calculations, but it will be necessary to guide it and especially with the oral examination as with the writing, to explain its step, the theorems used and their validity within the framework of this exercise. |
|
After have show that f(x) exist for any reality, that F be a function even (the field of study be thus [ 0, inf [), one show that F be derivable on ]0, inf ] and that:
| Without
" putting questions ", the TI-92 reasons like us.
The calculation of f' (x), for x>0, is then easy: |
|
|
|
|
| The
TI-92 finds only one value approximate.
It only remains to roll up the handles and to calculate: this integral is one of most traditional among those studied in prépa and we advise you to retain this pretty sequence of change of variables which lead to the solution. |
|
From where the value of I and f(1)=-Ì=pi*ln(2).
Therefore f(x)=pi*ln(1+x) for x>0.
The TI-92 lets to us suppose that f(0)=0 (see preceding screen).
Finally, f(x)=pi*ln(1+| x|)